| We can drop parentheses around the
quantity (3x5y) since it has an exponent
of 1. |
Solution |
2xy4(3x5y)(x3y5)2 |
| That is, (3x5y) = (3x5y)1
= 3x5y. |
Use the Power of a Product Property.
|
= 2xy4(3x5y)(x3·2y5·2) |
| |
Simplify.
|
= 2xy4(3x5y)(x6y10)
= 2xy4 · 3x5y
· x6y10 |
| Recall: x = x1 and y = y1 |
Multiply the constants, 2 and 3. |
= 6xy4 · x5y
· x6y10 |
| |
Use the Multiplication Property of Exponents.
|
= 6x1+5+6 y4+1+10 |
| So, 6xy4 = 6x1y4 and x5y
= x5y1. |
Simplify. |
= 6x12 y15 |
| |
So, the result is 6x12y15. |
|